(x+5)(x^2+2x-4)=

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Solution for (x+5)(x^2+2x-4)= equation:


Simplifying
(x + 5)(x2 + 2x + -4) = 0

Reorder the terms:
(5 + x)(x2 + 2x + -4) = 0

Reorder the terms:
(5 + x)(-4 + 2x + x2) = 0

Multiply (5 + x) * (-4 + 2x + x2)
(5(-4 + 2x + x2) + x(-4 + 2x + x2)) = 0
((-4 * 5 + 2x * 5 + x2 * 5) + x(-4 + 2x + x2)) = 0
((-20 + 10x + 5x2) + x(-4 + 2x + x2)) = 0
(-20 + 10x + 5x2 + (-4 * x + 2x * x + x2 * x)) = 0
(-20 + 10x + 5x2 + (-4x + 2x2 + x3)) = 0

Reorder the terms:
(-20 + 10x + -4x + 5x2 + 2x2 + x3) = 0

Combine like terms: 10x + -4x = 6x
(-20 + 6x + 5x2 + 2x2 + x3) = 0

Combine like terms: 5x2 + 2x2 = 7x2
(-20 + 6x + 7x2 + x3) = 0

Solving
-20 + 6x + 7x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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